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- Jan 26, 2012

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What is the target variable? That is, what is it for which you're trying to solve?

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- Jan 26, 2012

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Another way of saying what MarkFL said is this: can you write down a relevant, correct equation involving the target variable of distance?

I think the OP meant the kinematic equations, 4 basic ones meaning:A light plane must reach a speed of 33 m/s for takeoff. How long must the runway be if the plane has a constant acceleration of 3.8 m/s^{2}?

so, I am new to kinomatic equations. We are using the 4 Basic ones.

need to see this one worked out if I may.

Thanks

1) x=x

2) V=V

3) a=constant

4) V

If this is the case, the answer is a matter of determining starting values.

We can assume that the plane starts off at point 0 on the runway meaning that x

33m/s=0+(3.8m/s

t=(33/3.8)s

Now that we have a value for t, we can use equation 1 to find the total runway length, x, required to reach takeoff speed:

x=0+0(t)+1/2at

=(1/2)(3.8m/s

=143.30m

therefore the minimum amount of runway needed to reach the plane's necessary takeoff speed is 143.30 meters.