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I have posted a link there to this topic so the OP can see my work.Volume of a Solid using Calculus?

I am quite confused as to how to approach this. I know the volume will be the area between the curves but I haven't seen a problem like this before... Any help?

The base of a certain solid is an elliptical region with boundary curve 25x2+36y2=900. Cross-sections perpendicular to the x-axis are isosceles right triangles with hypotenuse in the base.

Use the formula V=∫baA(x)dx to find the volume of the solid.

The lower limit of integration is a =

The upper limit of integration is b =

The base of the triangular cross-section is the following function of x:

The height of the triangular cross-section is the following function of x:

The area of the triangular cross-section is A(x)=

Thus the volume of the solid is V=