Here is the question:
I have posted a link there to this topic so the OP can see my work.Volume of a Solid using Calculus?
I am quite confused as to how to approach this. I know the volume will be the area between the curves but I haven't seen a problem like this before... Any help?
The base of a certain solid is an elliptical region with boundary curve 25x2+36y2=900. Cross-sections perpendicular to the x-axis are isosceles right triangles with hypotenuse in the base.
Use the formula V=∫baA(x)dx to find the volume of the solid.
The lower limit of integration is a =
The upper limit of integration is b =
The base of the triangular cross-section is the following function of x:
The height of the triangular cross-section is the following function of x:
The area of the triangular cross-section is A(x)=
Thus the volume of the solid is V=