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anlenemilk
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Homework Statement
At take off, the rotor blades of a helicopter propel 2400 kg of air vertically downwards each second. The air, intially at rest, is given a speed of 11ms^-1
QN: the mass of the helicopter is 2500 kg. Find the acceleration of the helicopter as it starts to rise
Homework Equations
<F>=Change in momentum /change in time
Fnet=ma
The Attempt at a Solution
<F>=Change in momentum /change in time
= (2400*11-0)/1= 26400N
26400-2500(9.81)=(2500)a
a=0.75ms^-2
The answer is 9.58ms^-2
I have no idea how to get this answer! HELP ME! THANK YOU VERY MUCH