Accelaration & forces in different inertial referance frames

So, for instance, the mass of an object (which is the 0th component of the 4-momentum vector) is the same in all coordinate systems. You don't need to worry about transverse or longitudinal mass. And the momentum vector is (E/c, p_x, p_y, p_z), so it's really easy to see that dividing the mass by the slow speed of light, c, gives you E (which is the energy of the object), and multiplying the mass by the velocity gives you the momentum vector. That is, the components of the 4-momentum vector are E/c, p_x, p_y, p_z. And, unlike the transverse and longitudinal mass, the components of the
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arpon
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Are the accelaration and forces in different inertial referance frame equal ?
 
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Think about two observers moving at 1m/s less than c with respect to one another. What happens if one fires rockets to accelerate at 1g?
 
  • #3
arpon said:
Are the accelaration and forces in different inertial referance frame equal ?

No.

The post by Ibex suggests why, though when you factor in all the different relativistic effects, it's probably too hard to figure out all the details on one's own.

I'm not sure where the best reference is, Wiki has some discussion of the issues at http://en.wikipedia.org/wiki/Mass_in_special_relativity#Transverse_and_longitudinal_mass

The precise relativistic expression (which is equivalent to Lorentz's) relating force and acceleration for a particle with non-zero rest mass
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moving in the x direction with velocity v and associated Lorentz factor
334de1ea38b615839e4ee6b65ee1b103.png
is

618500998b5948db8a38d431d4faee68.png

f0c8e0593c7d431c3c0902bd7b481849.png

903f0ec2ebe281e3614a06f07082df64.png
 
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  • #4
arpon said:
Are the accelaration and forces in different inertial referance frame equal ?

I think your question has two different answers, depending on how you define "acceleration" and "force", and depending on what you mean by two vector quantities being equal.

Here are two different ways to define the acceleration of an object:
  1. Coordinate acceleration.
  2. "Proper" acceleration (which basically is acceleration relative to objects in freefall)
These are vector quantities, not numbers. There are two different ways to define equality of vector quantities:
  1. Component-wise equality.
  2. Covariant equality.
Let me illustrate the difference with something a little more mundane: Ordinary vectors in space. Suppose you are standing at an intersection, and there is an arrow pointing in some direction bearing the words "This way to Joe's restaurant". You might describe this arrow as pointing to the left. Then if you circle around the arrow, you might change your mind, and say that it is now pointing to right. So did the arrow change directions when you moved around? I would say no; your description of the arrow changed, because your notion of "left" and "right" changed, but the arrow didn't change.

The changes that happen to vectors (actually, 4-vectors, because in Special Relativity, there are 4 components to vectors; besides the usual 3 spatial components, there is also a time component) when you change reference frames can be thought of in the same terms. You can think of it as the vector as remaining constant, and only your description of the vector changes.

Coordinate acceleration definitely changes when you change reference frames, no matter how you slice it. Proper acceleration as a 4-vector can be thought of as remaining the same in all inertial reference frames, and the only thing that changes is the description of the 4-vector in terms of components.
 
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  • #6
arpon said:
Is there any straight forward way to prove these equations by using special relativity ?

It's straight-forward, but tedious.

I should point out, though, that the notion of "relativistic mass" is not used in modern physics, at all. So I really consider the effort to derive "transverse" and "longitudinal" mass to be a complete waste of effort. What's much more worth-while is to learn the modern way of doing Special Relativity, which is to use 4-vectors, whose components transform in a straight-forward way under a change of coordinates.
 

Related to Accelaration & forces in different inertial referance frames

What is acceleration?

Acceleration is a measure of the rate of change of velocity over time. It is typically measured in units of meters per second squared (m/s^2). An object can accelerate by either increasing or decreasing its velocity, or by changing its direction of motion.

What is a reference frame?

A reference frame is a set of coordinates used to describe the motion of an object. It provides a point of reference for measuring the position, velocity, and acceleration of an object. In physics, there are two types of reference frames: inertial and non-inertial.

What is an inertial reference frame?

An inertial reference frame is a reference frame in which Newton's first law of motion holds true. This means that an object at rest will remain at rest, and an object in motion will continue in a straight line at a constant speed, unless acted upon by an external force. In other words, there is no net force acting on an object in an inertial reference frame.

How do forces act in different inertial reference frames?

In different inertial reference frames, forces act in the same way. This is known as the principle of relativity, which states that the fundamental laws of physics are the same in all inertial reference frames. However, the observed effects of these forces may appear different due to differences in perspective and relative motion between reference frames.

How does acceleration change in different inertial reference frames?

Acceleration may appear different in different inertial reference frames, but the underlying physical laws remain the same. For example, the acceleration due to gravity is the same for all objects in free fall, regardless of their reference frame. However, the perceived acceleration may vary depending on the observer's frame of reference.

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