- Thread starter
- #1
Petrus
Well-known member
- Feb 21, 2013
- 739
Hello MHB,
solve \(\displaystyle ||x|-2|+|x+1|=3\)
and we find that \(\displaystyle x=0,-2,2,-1\)
I got problem to find the 'case',
Regards,
\(\displaystyle |\rangle\)
solve \(\displaystyle ||x|-2|+|x+1|=3\)
and we find that \(\displaystyle x=0,-2,2,-1\)
I got problem to find the 'case',
Regards,
\(\displaystyle |\rangle\)