A working example wrt the supremum norm

In summary, the conversation discusses an example of a sequence of functions that converges to a function with respect to the supremum norm. The example given is f_n(x)=\sum_{k=0}^n{\frac{x^k}{k!}}, which converges to f(x)=e^x and the convergence is uniform on each bounded set. The question then asks if this would also converge to the same function with respect to the integral norm, to which it is confirmed that it does. The conversation also mentions Dini's theorem, which states that under certain conditions, pointwise convergence implies uniform convergence. Finally, it is noted that LCKurtz' example can be generalized and it is suggested to explore what happens if
  • #1
bugatti79
794
1
Folks,

Could anyone give me a working example of a sequence of functions that converges to a function wrt to the supremum norm?

Thank you.
 
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  • #2
Depends on what you mean with "working example". A nice example is probably

[tex]f_n(x)=\sum_{k=0}^n{\frac{x^k}{k!}}.[/tex]

This converges to [itex]f(x)=e^x[/itex]. This convergence is uniform on each bounded set.
 
  • #3
micromass said:
Depends on what you mean with "working example". A nice example is probably

[tex]f_n(x)=\sum_{k=0}^n{\frac{x^k}{k!}}.[/tex]

This converges to [itex]f(x)=e^x[/itex]. This convergence is uniform on each bounded set.

Would this converge to the same function wrt to the integral norm?
 
  • #4
Yes. It is actually a nice exercise to show that it does. In fact, it suffices in this case to show that

[tex]\int_a^b|f_n|\rightarrow \int_a^b |f|[/tex]
 
  • #5
Pick a number a with ##0 < a < 1##. Let ##f_n(x) = x^n\hbox{ on }[0,a]##. Then ##\|f_n - 0\|\rightarrow 0##. Note that this fails if ##a=1##.
 
  • #6
LCKurtz' example is a really nice one! It is nice to notice that it can be generalized into what is known as Dini's theorem:

If [itex](X,d)[/itex] is a compact metric space and if [itex]f_n:X\rightarrow \mathbb{R}[/itex] are a sequence of functions such that
- They are monotonically decreasing/increasing
- They pointswize converge to a function f
- f is continuous
then the convergence is uniform.

It is one of the few cases where pointsiwize convergence implies uniform convergence.

LCKurtz' example follows with X=[0,a] (with 0<a<1), [itex]f_n(x)=x^n[/itex] and [itex]f(x)=0[/itex]. It is a nice exercise to see what goes wrong in the theorem if a=1.
 
  • #7
micromass said:
Depends on what you mean with "working example". A nice example is probably

[tex]f_n(x)=\sum_{k=0}^n{\frac{x^k}{k!}}.[/tex]

This converges to [itex]f(x)=e^x[/itex]. This convergence is uniform on each bounded set.

bugatti79 said:
Would this converge to the same function wrt to the integral norm?

Would it be something like this...


[itex]\displaystyle ||f_n(x)||_1=\int_{a}^{b}| \sum_{n=0}^{\infty} \frac{x^k}{k!}|dx[/itex] for c[a,b]
 
  • #8
LCKurtz said:
Pick a number a with ##0 < a < 1##. Let ##f_n(x) = x^n\hbox{ on }[0,a]##. Then ##\|f_n - 0\|\rightarrow 0##. Note that this fails if ##a=1##.

Hmmm..but regarding post 3 ie a function f_n the converges to the same function f on both sup and integral norms...this function does not converge to a function but to zero...?

micromass said:
LCKurtz' example is a really nice one! It is nice to notice that it can be generalized into what is known as Dini's theorem:

If [itex](X,d)[/itex] is a compact metric space and if [itex]f_n:X\rightarrow \mathbb{R}[/itex] are a sequence of functions such that
- They are monotonically decreasing/increasing
- They pointswize converge to a function f
- f is continuous
then the convergence is uniform.

It is one of the few cases where pointsiwize convergence implies uniform convergence.

LCKurtz' example follows with X=[0,a] (with 0<a<1), [itex]f_n(x)=x^n[/itex] and [itex]f(x)=0[/itex]. It is a nice exercise to see what goes wrong in the theorem if a=1.
 

Related to A working example wrt the supremum norm

What is the supremum norm?

The supremum norm, also known as the uniform norm, is a mathematical concept used to measure the size or magnitude of a function. It is defined as the maximum absolute value of a function over a given interval. In other words, it measures the largest vertical distance between the function and the x-axis.

How is the supremum norm calculated?

The supremum norm is calculated by finding the maximum absolute value of a function over a given interval. This can be done by graphing the function and visually identifying the highest point, or by using calculus to find the maximum value. It can also be calculated using computer software or programming languages such as MATLAB or Python.

What is an example of a function with a supremum norm?

One example of a function with a supremum norm is the function f(x) = x^2 on the interval [0,1]. The maximum absolute value of this function is 1, which occurs at x=1. This means that the supremum norm of this function on the interval [0,1] is 1.

How is the supremum norm useful in mathematics?

The supremum norm is useful in mathematics because it allows us to compare the size of different functions. It is also used in the definition of convergence of a sequence, and is a key concept in functional analysis and measure theory. In addition, it has applications in physics, engineering, and other fields where functions are used to model real-world phenomena.

Can the supremum norm be used for functions of more than one variable?

Yes, the supremum norm can be extended to functions of more than one variable. In this case, it is defined as the maximum absolute value of the function over a given region in the multidimensional space. This concept is important in multivariable calculus and optimization problems, where we need to find the maximum or minimum value of a function with multiple variables.

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