# A very interesting complex beta integral:

#### ZaidAlyafey

##### Well-known member
MHB Math Helper
This is one of the most interesting integrals I've ever seen

$$\frac{1}{2\pi i }\int^{c+i\infty}_{c-i\infty}t^{-a} (1-t)^{-b-1}\, dt = \frac{1}{b\,\beta(a,b)}$$

Does anybody have any idea how to prove it ?

#### Sudharaka

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MHB Math Helper
This is one of the most interesting integrals I've ever seen

$$\frac{1}{2\pi i }\int^{c+i\infty}_{c-i\infty}t^{-a} (1-t)^{-b-1}\, dt = \frac{1}{b\,\beta(a,b)}$$

Does anybody have any idea how to prove it ?
Hi ZaidAlyafey,

Is $$a$$ and/or $$b$$ integers?

#### ZaidAlyafey

##### Well-known member
MHB Math Helper
Hi ZaidAlyafey,

Is $$a$$ and/or $$b$$ integers?
Hi, when first I saw this equality there didn't seem to be this restriction , but let us
assume for simplicity that a and b are integers.

#### ZaidAlyafey

##### Well-known member
MHB Math Helper
I guess you are thinking about using residues in a way similar to the broomwich integral.

#### Sudharaka

##### Well-known member
MHB Math Helper
I guess you are thinking about using residues in a way similar to the broomwich integral.
Yeah, but I don't think I can find a way to get the required answer using that method. Where did you find this integral?

#### ZaidAlyafey

##### Well-known member
MHB Math Helper
Yeah, but I don't think I can find a way to get the required answer using that method. Where did you find this integral?
Well, after searching I got that which is called the Third(Cauchy's) beta integral :

$$\int^{\infty}_{-\infty}\frac{dt}{(1-it)^a(1+it)^b}= \frac{\pi 2^{2-a-b}\Gamma{(a+b-1)}}{\Gamma(a)\Gamma(b)}$$

Clearly our integral can be derived by doing a substitution , so this is a general formula
I found this in a paper SPECIAL FUNCTIONS AND THEIR SYMMETRIES by Vadim KUZNETSOV.