A question on Laplace transform

In summary, the conversation discusses the relationship between x(t) and y(t), with y(t) being the output and x(t) being the input. The question is how to derive Y(s)/X(s), and the suggestion is to expand the inverse term in its Taylor series form. However, this may lead to complications in the Laplace domain due to convolution. The speaker also questions the placement of x(t) in the denominator without specifying its meaning. They suggest that the function argument should include a time delay to reflect causality in input/output signals.
  • #1
Debdut
19
2
x(t) and y(t) are related by y(t)=1/(x(t) -k), how should I derive Y(s)/X(s)?
 
  • #3
I'm thinking of expanding the inverse term in its Taylor series form. But it would involve terms like (x(t))^2, (x(t))^3, etc if I am right. That would lead to convolution in Laplace domain which according to me is becoming more complicated!
 
  • #4
I cannot make sense of the question. Here is what I think, y is the "output" and x is the "input" and the relationship is supposed to be y(t) = 1 / x( t - k )
Note I have put the " - k " inside the function argument. This way it has y(t) depending on what x(t) was k seconds ago. This makes more sense since input/output signals in the time domain should be causal and not responding instantaneously. Although maybe I'm missing the point of the question entirely.
 
  • #5
Then again, why do they put x downstairs without even specifying what it is?
 

Related to A question on Laplace transform

1. What is a Laplace transform?

A Laplace transform is a mathematical tool used to solve differential equations. It transforms a function of time into a function of complex frequency, making it easier to solve the equation.

2. How is a Laplace transform used in science?

In science, Laplace transforms are commonly used to solve differential equations that describe physical systems. They are also used in signal processing, control theory, and other areas of engineering and physics.

3. What are the benefits of using a Laplace transform?

The main benefit of using a Laplace transform is that it simplifies the process of solving differential equations. It also allows for the use of more powerful techniques, such as complex analysis, to solve the equations.

4. Are there any limitations to using a Laplace transform?

One limitation of the Laplace transform is that it only works for linear systems. It also assumes that the system being studied is time-invariant, meaning that its behavior does not change over time.

5. How is a Laplace transform different from a Fourier transform?

A Laplace transform differs from a Fourier transform in that it takes into account both the magnitude and phase of a signal, while a Fourier transform only considers the magnitude. This makes the Laplace transform better suited for analyzing systems with feedback or control systems.

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