- #1
silenzer
- 54
- 0
A problem I should be able to solve :( (geometry)
This is a random problem I discovered on the internet:
If the area of a rectangle is diminished by 36%, what are the sides of the original rectangle if the sides of the diminished one are 36mm and 48mm?
My answer: Let a and b be the original sides (not diminished).
ab*0,64=1728, so ab=2700. We know that c/d = 36/48 = a/b = 3/4 so a = 3/4 b
Now: 3/4 b*b = 2700
So b^2 = 3600
And then b = +- sqrt of 3600, but since we want distance the answer is b=60.
Because a = 3/4 b, we get a = 3/4 * 60 = 45.
This is a random problem I discovered on the internet:
If the area of a rectangle is diminished by 36%, what are the sides of the original rectangle if the sides of the diminished one are 36mm and 48mm?
My answer: Let a and b be the original sides (not diminished).
ab*0,64=1728, so ab=2700. We know that c/d = 36/48 = a/b = 3/4 so a = 3/4 b
Now: 3/4 b*b = 2700
So b^2 = 3600
And then b = +- sqrt of 3600, but since we want distance the answer is b=60.
Because a = 3/4 b, we get a = 3/4 * 60 = 45.