- #1
littlejon
- 20
- 0
Homework Statement
Homework Equations
v(x)t= -wAsin(w+o)
The Attempt at a Solution
-5(10)sin(0)= 0
D
is this the right procedure?
A position versus time graph involving the unit circle
In summary, the conversation revolves around finding the correct equation for simple harmonic motion (SHM). The equation v(x)t= -wAsin(w+o) is incorrect and the correct equation is x(t) = . The first step is to determine the amplitude, which is not the same as wavelength. The conversation also suggests consulting notes, textbooks, or online resources for further information on SHM.
v(x)t= -wAsin(w+o)
-5(10)sin(0)= 0
D
is this the right procedure?
- #2
- 41,477
- 9,905
I'm not aware of any such equation. The equation you want is of the form x(t) = .littlejon said:
No.littlejon said:
The first step is to figure out the amplitude. Can you think how to read that off the graph?
- #3
littlejon
- 20
- 0
amplitude is 5
- #4
- 41,477
- 9,905
No. How did you arrive at that? How is the amplitude of an oscillation defined?littlejon said:
Have you found a correct equation?
- #5
littlejon
- 20
- 0
I just saw the wavelength and assumed it was 5.
- #6
lep11
- 380
- 7
This equation is wrong.littlejon said:
- #7
- 41,477
- 9,905
Amplitude is not wavelength. What do you think is meant by the amplitude of a wave?littlejon said:
You still haven't provided any correct equations related to SHM. Don't you have any notes or textbooks? If not, read it up online.
Related to A position versus time graph involving the unit circle
1. What is a position versus time graph involving the unit circle?
A position versus time graph involving the unit circle is a graph that shows the position of an object as it moves in a circular motion over time. The x-axis represents time and the y-axis represents the position of the object on the unit circle.
2. How is a position versus time graph involving the unit circle different from a regular position versus time graph?
A position versus time graph involving the unit circle differs from a regular position versus time graph in that the position is measured along the circumference of a circle instead of a linear path. This type of graph is used for objects that move in a circular motion, such as a pendulum or a planet orbiting the sun.
3. What does the slope of a position versus time graph involving the unit circle represent?
The slope of a position versus time graph involving the unit circle represents the angular velocity of the object. This is the rate at which the object is moving around the circle, measured in radians per second.
4. How can you determine the period of motion from a position versus time graph involving the unit circle?
The period of motion can be determined by finding the time it takes for the position to repeat itself on the graph. This can be done by finding the time between two consecutive peaks or troughs on the graph. The period is equal to the time it takes for one full rotation or revolution on the unit circle.
5. What is the relationship between the frequency of motion and the period on a position versus time graph involving the unit circle?
The frequency of motion is inversely proportional to the period on a position versus time graph involving the unit circle. This means that as the period increases, the frequency decreases and vice versa. The frequency is measured in Hertz (Hz) and represents the number of full rotations or revolutions per second.
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