A person moves a full sam's club shopping cart mass=80.0 kg from rest

  • Thread starter Ereny
  • Start date
  • Tags
    Cart Rest
In summary, a person moves a full Sam's Club shopping cart with a mass of 80.0 kg from rest to a velocity of 1.30 m/s over a distance of 1.80 meters to secure a spot in the check-out line. To find the time required for the cart to reach 1.30 m/s, we need to use the equation v = u + at, where v is the final velocity, u is the initial velocity (0 m/s), a is the acceleration, and t is the time. Without knowing the acceleration, we cannot determine the time. To determine the change in momentum of the cart, we use the equation p = mv, where p is the momentum, m is the mass
  • #1
Ereny
29
0
a person moves a full sam's club shopping cart mass=80.0 kg from rest to a velocity of 1.30 m/s over a distance of 1.80 meters to secure a spot in check out line.

A. find the time required to get the cart moving from rest to 1.30 m/s?

B. Determine the change in the chart's momentum?

c. determine the magnitude of the force exerted on the cart by the person.

D. the result from part c ignores friction. if the shopping cart's coefficient of friction is .40 determine the force required by the person to move the cart. (recall the friction force = UFn)
 
Physics news on Phys.org
  • #2
Hi Ereny! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 

Related to A person moves a full sam's club shopping cart mass=80.0 kg from rest

1. What is the force required to move a full Sam's Club shopping cart?

The force required to move a full Sam's Club shopping cart would depend on several factors, such as the surface on which the cart is being moved, the condition of the wheels, and the strength of the person pushing the cart. However, on average, it would require a force of around 80-100 Newtons to move an 80.0 kg cart from rest.

2. Why does it take more force to move a full shopping cart compared to an empty one?

This is because a full shopping cart has a greater mass compared to an empty one. According to Newton's Second Law of Motion, the force required to move an object is directly proportional to its mass. Therefore, a full shopping cart would require a greater force to overcome its inertia and start moving compared to an empty one.

3. Can the force required to move a shopping cart be reduced?

Yes, the force required to move a shopping cart can be reduced by lubricating the wheels, ensuring they are in good condition, and pushing the cart on a smooth surface. Additionally, using proper body mechanics and distributing the weight evenly while pushing can also reduce the force required.

4. How does the speed of the cart affect the force required to move it?

The speed of the cart does not affect the force required to move it. According to Newton's First Law of Motion, an object will maintain its state of motion unless acted upon by an external force. Therefore, the force required to move the cart would remain the same regardless of its speed.

5. Is it possible to calculate the exact force required to move a shopping cart?

It is not possible to calculate the exact force required to move a shopping cart as it would depend on various factors such as the surface, wheels, and person pushing the cart. However, using Newton's Second Law of Motion, an estimation of the force required can be made based on the mass of the cart and assuming ideal conditions.

Similar threads

  • Introductory Physics Homework Help
Replies
18
Views
2K
  • Introductory Physics Homework Help
Replies
24
Views
2K
  • Introductory Physics Homework Help
Replies
15
Views
3K
  • Introductory Physics Homework Help
Replies
3
Views
4K
  • Introductory Physics Homework Help
Replies
6
Views
6K
  • Introductory Physics Homework Help
Replies
11
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
7K
  • Introductory Physics Homework Help
Replies
12
Views
4K
  • Introductory Physics Homework Help
Replies
3
Views
9K
  • Introductory Physics Homework Help
Replies
20
Views
2K
Back
Top