A little electronics question about logical gates

  • Thread starter Femme_physics
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    Electronics
In summary, the conversation involves a discussion on simplifying a logical gate using the basic laws of Boolean algebra. The participants use a truth table to visualize the inputs and outputs of the gate and then proceed to simplify it using the distributive law and other rules of Boolean algebra. The final answer is determined to be the variable "c" after simplification.
  • #36


Femme_physics said:
True, but at the end of the day the result is still 0 cause we got a and a(capped) in the same multiplication line so everything gets nullified, right?

Actually, you don't have ##\overline{a}##, but you have ##\overline{ab}##.
But yes, in combination with ##ab##, everything gets nullified.
 
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  • #37


I like Serena said:
Actually, you don't have ##\overline{a}##, but you have ##\overline{ab}##.
But yes, in combination with ##ab##, everything gets nullified.

Ah, gotcha! Now I am asked to write the logical value of the function Out, when the values of all the ports
C = '0'
A = B = '1'

But still, everything gets nullified right?
 
  • #38


Hold on, I missed something.

It does not get nullified.

You got ##\overline{\overline{ab}c}##, which you took to ##abc##, but that is not right.
That changes everything.
 
Last edited:
  • #41


Could you add parentheses in the 3rd line?
 

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