A horizontal force of 100 N is applied a block solve this

In summary, a horizontal force of 100 N is applied to a block on a friction-less surface, resulting in an acceleration of 3m/s^2. The mass of the block is 33.33 kg. If the force is applied for 10 seconds, the block will travel a distance of 150m and have a speed of 30m/s after 10 seconds.
  • #1
wein7145
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Homework Statement


1) A block lies on a horizontal friction-less surface. A horizontal force of 100 N is applied to the block giving rise to an acceleration of 3m/s^2.

(a) Determine the mass of the block.
b)Calculate the distance the block will travel if the force is applied for 10s.
c)Calculate the speed of the block after the force has been applied for 10s.

Homework Equations


Force=mass*(acceleration)
distance = 1/2*a*t^2
velocity = a*t

The Attempt at a Solution


a) I'm pretty sure it's just Force/accel =mass so 100N/3m/s^2=33.33kg (Edit kg not N)
b) distance = 1/2*a*t^2 = 1/2*3 m/s^2 * (10s)^2 = 150 m
c) velocity = a*t = 3 m/s^2 * 10s = 30 m/s
Just check over my work. At least I feel like I'm learning something this week.
 
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  • #2
wein7145 said:

Homework Statement


1) A block lies on a horizontal friction-less surface. A horizontal force of 100 N is applied to the block giving rise to an acceleration of 3m/s^2.

(a) Determine the mass of the block.
b)Calculate the distance the block will travel if the force is applied for 10s.
c)Calculate the speed of the block after the force has been applied for 10s.

Homework Equations


Force=mass*(acceleration)
distance = 1/2*a*t^2
velocity = a*t

The Attempt at a Solution


a) I'm pretty sure it's just Force/accel =mass so 100N/3m/s^2=33.33N
b) distance = 1/2*a*t^2 = 1/2*3 m/s^2 * (10s)^2 = 150 m
c) velocity = a*t = 3 m/s^2 * 10s = 30 m/s
Just check over my work. At least I feel like I'm learning something this week.

In a) the units of mass are not Newtons.
 
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  • #3
In a) the units of mass are not Newtons.
Whoops your right they are kg (Kilograms) But does everything else look good?
 
  • #4
wein7145 said:
Whoops your right they are kg (Kilograms) But does everything else look good?
Yes, everything else seems to be OK.
 
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Related to A horizontal force of 100 N is applied a block solve this

1. What is the magnitude of the applied force?

The magnitude of the applied force is 100 Newtons.

2. What is the direction of the applied force?

The direction of the applied force is horizontal, meaning it is parallel to the surface of the block.

3. What is the weight of the block?

The weight of the block is not provided in the given information. It depends on the mass of the block and the acceleration due to gravity.

4. What is the acceleration of the block?

Using Newton's Second Law (F=ma), we can rearrange the equation to find the acceleration (a=F/m). Without knowing the mass of the block, we cannot determine the acceleration.

5. How do you solve for the net force on the block?

In order to solve for the net force on the block, we need to know the weight of the block and the applied force. The net force is the vector sum of all the forces acting on the block. In this case, it would be the sum of the applied force and the weight of the block (assuming no other forces are acting on the block).

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