- Thread starter
- Admin
- #1

Consider the region within a square containing the points which are closer to the center of the square than to any of the sides. What portion of the square is this region?

I am curious to see what other methods may be used to solve this. I will post my method if it differs from those anyone else may give.

This is the result I get:

$\displaystyle 2\left(\sqrt{6}-\frac{7}{3} \right)$