A cylinder rolls without slipping- find the angle

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Homework Statement

A cylinder with radius R and mass M rolls without slipping down an incline plane with angle[tex]\theta[/tex]. The coeff. of friction is [tex]\mu[/tex]. Find the maximum value for the angle for the cylinder to roll without slipping.

Homework Equations

The moment of inertia for a cylinder is I=(MR^2)/2.
w=v/r

The Attempt at a Solution

If the cylinder rolls without slipping, energy must be conserved. So Mgh=1/2Mv^2+1/2Iw^2. If you plug in the equations from above and divide all terms by M, gh=3/4v^2.
So we need to find v.
The equation for the x-component of force (where x is along the plane of the incline), F=mg(cos[tex]\theta[/tex]-[tex]\mu[/tex])=ma
and the y-component
F=0=N-mgsin[tex]\theta[/tex] or N=mgsin[tex]\theta[/tex]

I have no idea where to go from here and I'm not quite sure I did all of this right. Thank you so much for any help!

 

[Tzim]

You should think when you will have the minimum value of angle.When you have the maximum of static friction.Also i think you have a mistake.In the direction of the slope the forces are Wy=mgsinθ and T<=μN

 

[Tzim]

Also N=mgcosθ not mgsinθ