A cube of side L=2 m is made of a cooper cable with 2mm^2

In summary, the conversation discusses finding the electric resistance of one side of a cube with a side length of 2m and a cross-sectional area of 2mm^2. The first statement is completed by using the formula R=ρL/A, where ρ is the resistivity of the material, L is the length, and A is the area. The electric resistance is approximately 0.0172Ω. The second statement involves finding the equivalent resistance between points A and B, taking into account the symmetry of the cube and the flow of current through the edges.
  • #1
GaussianSurface

Homework Statement


A cube of side L=2m is made of a cooper cable with 2mm^2 of cross section area.
1) Find the electric resistance of one side of the cube.
2) Find the equivalent resistance in between the points A and B.
 

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  • #2
Actualization: I've done the first statement. By doing this:
The electrical resistivity is defined with the formula R=ρL/A where ρ is the resistivity of the material measured in Ω*m, L is the length in meters and A is the Area measured in m^2.
So that it is:
L=2m
R=?
A=2mm²=2*10^-6m²
ρ= 1.72*10^-8
Replacing these terms in the formula is equal to ≈ 0.0172Ω
I got the first one but the second one I still confused.
 
  • #3
GaussianSurface said:
the second one I still confused.
You can make good use of the symmetry.
Suppose you apply some voltage across A and B and a current I flows in one of the edges out of A. What current flows along the other edges out of A? What about the six edges those three edges lead to?
 

Related to A cube of side L=2 m is made of a cooper cable with 2mm^2

1. What is the volume of the cube?

The volume of a cube is calculated by multiplying the length, width, and height together. In this case, the length (L) is given as 2 meters, so the volume would be 2m x 2m x 2m = 8m^3.

2. How much copper cable is needed to make the cube?

To calculate the amount of copper cable needed, we first need to find the surface area of the cube. This is done by multiplying the length of one side by itself, then multiplying that by 6 (since a cube has 6 sides). In this case, the surface area would be 2m x 2m x 6 = 24m^2. Then, we can convert the surface area to square millimeters (mm^2) by multiplying by 1,000,000. So, the total amount of copper cable needed would be 24 million mm^2.

3. What is the resistance of the copper cable?

The resistance of a material is dependent on its length, cross-sectional area, and resistivity. In this case, the length (L) is given as 2 meters and the cross-sectional area is 2mm^2. The resistivity of copper is typically around 1.68 x 10^-8 ohm-meters. So, the resistance would be calculated as (1.68 x 10^-8 ohm-meters x 2m) / 2mm^2 = 3.36 x 10^-5 ohms.

4. How much weight can the cube hold before breaking?

The weight a cube can hold before breaking depends on several factors, such as the material strength and the distribution of weight. Without knowing these factors, it is difficult to determine an exact weight limit for this specific cube. However, copper is a relatively strong material and can typically withstand a significant amount of weight without breaking.

5. How does the cube's material affect its properties?

The material of an object can greatly affect its properties, such as its strength, electrical conductivity, and melting point. In the case of this copper cube, the material's high electrical conductivity makes it a good choice for applications involving electricity, but its relatively low melting point (around 1084.62 degrees Celsius) may limit its use in high-temperature environments.

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