- #1
newton1
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how to solve the x from x^4+x^3...=...??
i mean from the equation for x power of 4
like the x^2-2x+1=0
the solve are x=1,x=1
i mean from the equation for x power of 4
like the x^2-2x+1=0
the solve are x=1,x=1
Originally posted by Loren Booda
How effective is the p/q method for finding roots of quartics or higher order polynomials? Remind me how it works for a simple example.
To solve an equation with x^4, you need to set it equal to a number. For example, if the equation is x^4 = 16, you can solve by taking the fourth root of both sides, which gives x = ±2.
The process for solving x^4 equations is similar to solving other equations with exponents. First, set the equation equal to a number. Then, take the appropriate root of both sides (in this case, the fourth root). Finally, solve for x by using any necessary algebraic techniques.
No, the quadratic formula is used to solve equations with x^2 as the highest power. For x^4 equations, you would need to take the fourth root of both sides and then solve for x using algebraic techniques.
If the equation is in the form ax^4 = b, you can simply divide both sides by a before taking the fourth root. This will give you the solution for x without the coefficient.
One special case is when the equation has a negative exponent, such as x^-4. In this case, you would need to take the fourth root of both sides and then take the reciprocal to get the solution for x.