- Thread starter
- #1

#### veronica1999

##### Member

- Jun 4, 2012

- 63

For p there are only 10 cases when all the numbers are the same.

For q there would be a lot more cases.

First, there will be 10C2 ways to choose the two numbers then i have to think of the ways the number can be arranged. xxyy can be arranged in 6 ways and then i have to multiply by two because the number x and y can be switched.

So my answer is 10C2X6X2/40C4 over 10/40C4

I am not sure why my answer is wrong.