- Thread starter
- #1

#### karush

##### Well-known member

- Jan 31, 2012

- 2,724

motion formula $v=u+at$

so

$v = 6.00 \dfrac{m}{s}

+ 9.81 \dfrac{m}{s^{\cancel{2}}}{2.00 \cancel{s}}

= 27.6 \dfrac{m}{s}$

b) How far does it fall in 2.00s

distance formula $d= ut + \dfrac{1}{2}at^2$

so

$d=6.00\dfrac{m}{\cancel{s}}\cdot 2.00\cancel{s}

+ \dfrac{1}{2}\cdot 9.81 \dfrac{m}{s^{\cancel{2}}}{(2.00s)^2}

=12.00m+19.62m=31.6m$

c) What is the magnitude of its velocity after falling 10.0m?

graph $a-t, v-t, \textit{ and } y-t$ graphs for the motion.

ok don't have book answer to these and a little ?? on c} and graph