- Thread starter
- #1

- Thread starter dwsmith
- Start date

- Thread starter
- #1

- Jan 30, 2012

- 2,532

- Thread starter
- #3

I don't need a x,y,z axis. A cube in free space only with vectors. I still need help.

- Jan 30, 2012

- 2,532

Code:

```
\usetikzlibrary{arrows}
\begin{tikzpicture}[>=stealth',x=2cm,y=2cm,z=0.77cm]
\fill (0,0) circle (1.5pt);
\draw (0,0) -- (1,0) -- (1,1) -- (0,1) -- cycle;
\begin{scope}[shift={(0,0,1)}]
\draw (0,0) -- (1,0) -- (1,1) -- (0,1) -- cycle;
\end{scope}
\draw (0,0) -- (0,0,1) (0,1) -- (0,1,1) (1,0) -- (1,0,1) (1,1) -- (1,1,1);
\end{tikzpicture}
```

For the description of the XYZ coordinate system, see section 22.2 on p. 249 in the v. 2.10 TikZ manual.

- Thread starter
- #5

This is one way.

View attachment 362Code:`\usetikzlibrary{arrows} \begin{tikzpicture}[>=stealth',x=2cm,y=2cm,z=0.77cm] \fill (0,0) circle (1.5pt); \draw (0,0) -- (1,0) -- (1,1) -- (0,1) -- cycle; \begin{scope}[shift={(0,0,1)}] \draw (0,0) -- (1,0) -- (1,1) -- (0,1) -- cycle; \end{scope} \draw (0,0) -- (0,0,1) (0,1) -- (0,1,1) (1,0) -- (1,0,1) (1,1) -- (1,1,1); \end{tikzpicture}`

For the description of the XYZ coordinate system, see section 22.2 on p. 249 in the v. 2.10 TikZ manual.

Code:

```
\begin{tikzpicture}[>=stealth',x = 2cm,y = 2cm,z = 0.77cm]
\draw[->] (.9,159/110,0)-- (-.5,-107/110,0) node[anchor = south east]{$\frac{\partial }{\partial y}$};
\draw[->] (-1.3,.15) -- (1.5,.15) node[anchor = north east]{$\frac{\partial }{\partial x}$};
\draw[->] (.15,-1.3) -- (.15,1.5) node[anchor = north east]{$\frac{\partial }{\partial z}$};
\draw (-.5,-.5) -- (.5,-.5) -- (.5,.5) -- (-.5,.5) -- cycle;
\begin{scope}[shift = {(0,0,1)}]
\draw (-.5,-.5) -- (.5,-.5) -- (.5,.5) -- (-.5,.5) -- cycle;
\end{scope}
\draw (-.5,-.5) -- (-.5,-.5,1) (.5,-.5) -- (.5,-.5,1) (.5,.5) -- (.5,.5,1) (-.5,.5) -- (-.5,.5,1);
\end{tikzpicture}
```