- #1
jlawson
- 5
- 0
To my knowledge I assume:
Newton's second law of motion :
F = ma = mx''
Hooke's Law
F = ks where s is the distance displaced by the mass.
When a mass is attached to the spring, the new spring force is:
F = k(s+x)
While the downward force is still:
mg
If the two forces are equal and opposite, then:
mg = k(s+x) after simplifying
kx=0
***********************
My question is: From kx=0, how do I get:
F=kx
I know how this leads to the final equation mx''-kx=0
But do we just assume that kx is a force and set it equal to F. I just don't understand the reasoning.
Newton's second law of motion :
F = ma = mx''
Hooke's Law
F = ks where s is the distance displaced by the mass.
When a mass is attached to the spring, the new spring force is:
F = k(s+x)
While the downward force is still:
mg
If the two forces are equal and opposite, then:
mg = k(s+x) after simplifying
kx=0
***********************
My question is: From kx=0, how do I get:
F=kx
I know how this leads to the final equation mx''-kx=0
But do we just assume that kx is a force and set it equal to F. I just don't understand the reasoning.