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#### karush

##### Well-known member

- Jan 31, 2012

- 2,886

use the different techniques of diagonal, diagonalizedable, or triangular.

$\begin{cases}

y'_1 & =3y_1 \\ y'_2 & =2y_2\end{cases}$

set matrix

$A= \begin{pmatrix}0 &3\\0 &2\end{pmatrix}$

then find eigenvalues

ok just seeing if i am starting out correctly with this..

not sure what the difference is between diagonal and diagonalizedable? but it looks diagonal