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#### karush

##### Well-known member

- Jan 31, 2012

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$\left(e^{-2t/3} y \right)' = \dfrac{1}{3}e^{-(3\pi+4)t/6}$

$e^{-2t/3} y = -\dfrac{2}{3\pi+4}e^{-(3\pi+4)t/6} + C$

$y = Ce^{2t/3} -\dfrac{2}{3\pi+4}e^{-\pi t/2}$

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mahalo

noticed there was 430+ views on this one

noticed there was 430+ views on this one