[SOLVED]23 solve initial value problem

karush

Well-known member
given #23

so far

I could not get to the W|A solution before applying the y(0)=a

here is the book answer for the rest

skeeter

Well-known member
MHB Math Helper
$e^{-2t/3} y' - \dfrac{2e^{-2t/3}}{3} y = \dfrac{1}{3}e^{-(3\pi+4)t/6}$

$\left(e^{-2t/3} y \right)' = \dfrac{1}{3}e^{-(3\pi+4)t/6}$

$e^{-2t/3} y = -\dfrac{2}{3\pi+4}e^{-(3\pi+4)t/6} + C$

$y = Ce^{2t/3} -\dfrac{2}{3\pi+4}e^{-\pi t/2}$

karush

Well-known member
mahalo
noticed there was 430+ views on this one