- #1
MikeH
- 29
- 0
I have to find the principal root of [tex]\sqrt[3]{8 i}[/tex]
But I get stuck at this part
change this to polar coordinates...
[tex]r= \sqrt {x^2 + y^2} [/tex]
which makes [tex]r=8[/tex]
but when I try to find [tex]\theta[/tex]
[tex]\theta = \arctan \frac{y}{x}[/tex]
from the original x = 0 so how do I find [tex]\theta[/tex]?
But I get stuck at this part
change this to polar coordinates...
[tex]r= \sqrt {x^2 + y^2} [/tex]
which makes [tex]r=8[/tex]
but when I try to find [tex]\theta[/tex]
[tex]\theta = \arctan \frac{y}{x}[/tex]
from the original x = 0 so how do I find [tex]\theta[/tex]?