- Thread starter
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#### karush

##### Well-known member

- Jan 31, 2012

- 2,685

where t is the number of minutes since the pump was turned on.

If the tank contained 800 gallons of water when the pump was turned on,

how much water, to the nearest gallon, is in the tank after 20 minutes?

\begin{array}{ll}

a. &380 \textit{ gal}\\

b. &420\textit{ gal}\\

c. &829\textit{ gal}\\

d. &1220\textit{ gal}\\

e. &1376\textit{ gal}

\end{array}

so starting take the integral

why is e in the d/dt

$$\displaystyle800-\int_0^{20} 30(1- e^{-0.16t})\ dt $$