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2.4.1 find interval

karush

Well-known member
Jan 31, 2012
2,886
2.4.1.PNG
doing #1

ok first I divided thru

$$y' + \frac{\ln{t}}{t-3}y=\frac{2t}{t-3}$$

but the $$\exp\int p(t) \, dt$$ step kinda baloated???

ok I see the denominator has $t-3$ so presume 3 is one of the interval ends
but why 0. ?

book answwer is

2.4.1-6a.PNG
 

Country Boy

Well-known member
MHB Math Helper
Jan 30, 2018
731
"Baloated"?

The reason for the restriction x> 0 is the "ln(x)" term.
 

karush

Well-known member
Jan 31, 2012
2,886

Country Boy

Well-known member
MHB Math Helper
Jan 30, 2018
731
I am not sure what you are asking. Do you know what "$Li_2(x)$" is?
 

topsquark

Well-known member
MHB Math Helper
Aug 30, 2012
1,181
yeah how would this really work $e^{p}$
But your problem statement said not to solve the equation. So why are you introducing the \(\displaystyle e^p\) into your solution?

-Dan