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Sariaht
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What is the acceleration of a particle orbiting around a nucleus?
v/(4(pi)) = a ?
I cannot find this info... Will you help me?
r = r0
v/(4(pi)) = a ?
I cannot find this info... Will you help me?
r = r0
Originally posted by himanshu121
Thanks!
wait... is it really?
Originally posted by himanshu121
like... so this statement: (ec)2/(107*r2) = a is not true?
Acceleration is the rate of change of an object's velocity over time. It is a vector quantity, meaning it has both magnitude (speed) and direction.
The acceleration of a particle orbiting around a nucleus is caused by the electric force between the two objects. This force acts as a centripetal force, constantly changing the direction of the particle's velocity and causing it to accelerate towards the nucleus.
The acceleration of a particle orbiting around a nucleus is affected by the mass of the particle, the mass of the nucleus, and the distance between them. The greater the mass of the particles or the smaller the distance between them, the greater the acceleration will be.
The acceleration of a particle orbiting around a nucleus can be calculated using Newton's second law of motion, which states that the net force on an object is equal to its mass times its acceleration (F = ma). In this case, the net force is the electric force between the particle and nucleus.
Yes, the acceleration of a particle orbiting around a nucleus is constant. This is because the force of gravity between the particle and nucleus is always present and acting in the same direction, causing the particle to continuously accelerate towards the nucleus at a constant rate.