elitewarr said:Homework Statement
For complete oxidation, 1mol of an organic compound requires 3mol of oxygen gas
What could be the formula?
a) CH3CHO
b) CH3CH2OH
c) CH3CH3
d) CH3CO2H
Homework Equations
The Attempt at a Solution
What does it mean by complete oxidation? Is it combustion?
chemisttree said:Yes it is combustion.
When a statement mentions that 1mol of an organic compound requires 3mol of oxygen gas, it is referring to the stoichiometric ratio between the two substances in a chemical reaction. This means that for every 1mol of the organic compound, 3mol of oxygen gas are needed to complete the reaction and form the desired products.
Oxygen gas is necessary in the reaction of an organic compound because it acts as an oxidizing agent. This means that it helps transfer electrons from the organic compound to other substances involved in the reaction, leading to the formation of new products. In organic chemistry, oxygen gas is often used as a reactant in the combustion of organic compounds.
No, the stoichiometric ratio between an organic compound and oxygen gas can vary depending on the specific reaction and the nature of the organic compound. Some reactions may require more or less oxygen gas, depending on the number of carbon atoms present in the organic compound and the desired products.
If there is an excess of oxygen gas in the reaction, it will not be fully consumed and will remain in the products. On the other hand, if there is a deficiency of oxygen gas, the reaction may not be able to fully proceed, resulting in a lower yield of the desired products. It is important to carefully control the amount of oxygen gas used in a reaction to achieve the desired results.
Yes, the stoichiometric ratio between an organic compound and oxygen gas can be altered by using different reactants or adjusting the reaction conditions. For example, using a different oxidizing agent or changing the temperature and pressure can affect the amount of oxygen gas required in a reaction. However, this may also alter the products formed, so it is important to carefully consider the desired outcome before altering the stoichiometric ratio.