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proxy98
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1-D Perfectly Elastic Collison PLEASE CHECK! THANKS
Mass m1 is moving to the right at a velocity of 17.6m/s. Suddenly it strikes a stationary ball. The stationary ball has a mass of .685kg. The collision is perfectly elastic and 1 dimensional. The collision forces m2 to move to the right at 11.1m/s (v2prime).
Total momentum = 5.5 kg m/s ??
m1 = .3155kg ??
v1prime= -6.5m/s ??
momentum before = momentum after
m1v1 = m1v1prime + m2v2prime
v2prime = (2m1)/(m1+m2) (v1) + (m2-m1)/(m1+m2) (v2)
v1prime = (m1-m2)/(m1+m2) (v1) + (2m2)/(m1+m2) (v2)
11.1(m1+.685) = 35.2m
11.1m1 + 7.6035 = 35.2m
24.1m = 7.6035
m1= .3155 kg
v1prime = (.316-.685)/(.316+.685)(17.6) + 0 (v2 = 0)
v1prime = -6.50 m/s Left.
momentum before = momentum after
(17.6)(.316) = (.316)(-6.5) + (.685)(11.1)
5.55 kgm/s
Thanks for taking your time to help ! I just want to make sure this is right.
Homework Statement
Mass m1 is moving to the right at a velocity of 17.6m/s. Suddenly it strikes a stationary ball. The stationary ball has a mass of .685kg. The collision is perfectly elastic and 1 dimensional. The collision forces m2 to move to the right at 11.1m/s (v2prime).
Total momentum = 5.5 kg m/s ??
m1 = .3155kg ??
v1prime= -6.5m/s ??
Homework Equations
momentum before = momentum after
m1v1 = m1v1prime + m2v2prime
v2prime = (2m1)/(m1+m2) (v1) + (m2-m1)/(m1+m2) (v2)
v1prime = (m1-m2)/(m1+m2) (v1) + (2m2)/(m1+m2) (v2)
The Attempt at a Solution
11.1 = (2*m1)/(m1+.685) ( 17.6) + 0 (cancels cause m2 is stationary11.1(m1+.685) = 35.2m
11.1m1 + 7.6035 = 35.2m
24.1m = 7.6035
m1= .3155 kg
v1prime = (.316-.685)/(.316+.685)(17.6) + 0 (v2 = 0)
v1prime = -6.50 m/s Left.
momentum before = momentum after
(17.6)(.316) = (.316)(-6.5) + (.685)(11.1)
5.55 kgm/s
Thanks for taking your time to help ! I just want to make sure this is right.