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#### karush

##### Well-known member

- Jan 31, 2012

- 2,678

View attachment 9539

$\displaystyle g'=2xe^{kx}+e^{kx}kx^2$

we are given $ x=\dfrac{2}{3}$ then

$\displaystyle g'=\dfrac{4}{3}e^\left(\dfrac{2k}{3}\right)+e^\left({\dfrac{2k}{3}}\right)\dfrac{4k}{9}$

ok something is ??? aren't dx supposed to set this to 0 to find the critical point

did a desmos look like k=-3 but ???

$\displaystyle g'=2xe^{kx}+e^{kx}kx^2$

we are given $ x=\dfrac{2}{3}$ then

$\displaystyle g'=\dfrac{4}{3}e^\left(\dfrac{2k}{3}\right)+e^\left({\dfrac{2k}{3}}\right)\dfrac{4k}{9}$

ok something is ??? aren't dx supposed to set this to 0 to find the critical point

did a desmos look like k=-3 but ???

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