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(0,a) , (b,0) , (2,d) and (e,7) lie on y=2x+1, find a, b, d and e

Parthyy

New member
Jan 25, 2019
1
A STRAIGHT LINE has equation y=2x+1. The point coordinates (0,a) , (b,0) , (2,d) and (e,7) lie on this line. Find the values of a,b,d, and e.
 

topsquark

Well-known member
MHB Math Helper
Aug 30, 2012
1,120
A STRAIGHT LINE has equation y=2x+1. The point coordinates (0,a) , (b,0) , (2,d) and (e,7) lie on this line. Find the values of a,b,d, and e.
You have an equation y = 2x + 1 and several ordered pairs on that line.

So for the first, (0, a) we have
\(\displaystyle a = 2(0) + 1 = 1\)

Thus a =1. Can you finish?

-Dan
 

Country Boy

Well-known member
MHB Math Helper
Jan 30, 2018
368
A STRAIGHT LINE has equation y=2x+1. The point coordinates (0,a) , (b,0) , (2,d) and (e,7) lie on this line. Find the values of a,b,d, and e.
Each pair represents (x, y). The line is given as y= 2x+ 1 so (0, a) must satisy a= 2(0)+ 1. similarly, (b, 0) must satisfy 0= 2b+ 1. Solve that equation for b. (2, d) must satisfy d= 2(2)+ 1. (e, 7) must satisfy 7= 2e+ 1. Solve that equation for e.