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  1. MHB Craftsman

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    #1
    A gym offers a variety of weights for use by its mem-bers. If there are 6 more 50-pound weights than 100-pound weights and three times as many 20-pound
    weights as 50-pound weights, for a total of 3180
    pounds, how many of each weight are there?

    this is howi solved it,

    let
    $x=$ # of 100 pound weights
    $x+6=$ # of 50 pound weights
    $3(x+6)=$ # of 20 pound weights

    my equation,

    $x+x+6+3(x+6)=3180=2x+3x+24=3180=5x+24=3180$ and then $x=631.2$

    there are 631.2 (100 pound weights), 637.2(50 pound weeights), and 1911.6 (20 pound weights)

    but my answers didn't make sense. because it's not a whole number. i expect to get a whole number.

    can you help me with this. thanks.

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  3. Pessimist Singularitarian
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    #2
    You are using the number of weights rather than the weight of each set in your equation. You want:

    $ \displaystyle x(100\text{ lb})+(x+6)(50\text{ lb})+3(x+6)(20\text{ lb})=3180\text{ lb}$

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