Facebook Page
Twitter
RSS
+ Reply to Thread
Results 1 to 2 of 2
  1. MHB Apprentice

    Status
    Offline
    Join Date
    May 2014
    Posts
    1
    Thanks
    0 times
    Thanked
    0 times
    #1
    Hello, I'm in need of major help on some equations.. I have an exam coming up for finals and I'm horrid at algebra in general. I'm in intermediate algebra for the second time. Soo.. yeah, help would be greatly appreciated. Thank you! (Please explain step by step.)

    1. Rationalize the denominator, assume all variables represent positive numbers:
    √81/5 and ^3√5/9x^2

    2. Solve: √4q+5=5 and √3x+1=3+√x-4

    3. Find the LCM: 35x, 5x^2, 7x^3 ( I tried this over and over and could not figure it out. There are answers given to chose from. None of the answers matched. )

    4. Perform the indicated operation: 3x/10x - 9/14x^2

    5. Simplify: 12m^2p^2/4m^10p

    6: Divide (and simplify): 3x^2/5 / x^3/30

    7. Find the domain of f: f(x)= x/4x+3

    Thank you for your help! I really appreciate it!

  2. # ADS
    Circuit advertisement
    Join Date
    Always
    Posts
    Many
     

  3. MHB Master
    MHB Site Helper
    MHB Math Scholar

    Status
    Offline
    Join Date
    Jan 2012
    Posts
    2,483
    Thanks
    533 times
    Thanked
    4,408 times
    Thank/Post
    1.775
    Awards
    MHB University Math Award (2018)  

MHB Humor Award (2017)  

MHB Discrete Mathematics Award (2017)  

MHB Chat Room Award (2016)  

MHB Humor Award (2016)
    #2
    Hi, and welcome to the forum!

    Please familiarize yourself with the , especially rules #8 and 11. As you see, there is some conflict between the requirement that you show some effort and your shortage of time before the test. This may not be the perfect resource for the last-minute help, but let us try to find a middle ground.

    I am sure you have a textbook that describes how to solve these types of problems, and you have been presented with example solutions. I think the best you can do is to go back and read that material. Why do you think that what someone writes here would be better than explanations in your textbook? Now, if those explanations are unclear, then please describe your difficulty and we would be happy to help. Describing your problem and showing what you do and don't understand definitely counts as an effort.

    I believe many formulas you wrote are not what you in fact intended because of the order of operations. For example, in problem 7 you must mean f$(x)= x/(4x+3)$, that is, $f(x)=\dfrac{x}{4x+3}$. As it is written, $f(x)= x/4x+3$ means $f(x)=\dfrac{x}{4}x+3$. Similarly, $3x/10x$ in problem 4 strictly speaking means $\dfrac{3x}{10}x=\dfrac{3x^2}{10}$ because multiplication and division are done left to right. You don't need to know how to write fractions vertically because all formulas can be written correctly as plain text using parentheses. For example, in problem 2 you probably mean √(3x+1) and not (√3)x+1. Please rewrite your problems putting no more than two in one thread.

    One solution.

    Quote Originally Posted by Jinxxerz View Post
    3. Find the LCM: 35x, 5x^2, 7x^3
    First, recall how to divide two monomials. If $a,b$ are real numbers and $m,n$ are integers, then
    \[
    \frac{ax^m}{bx^n}=\frac{a}{b}\cdot\frac{x^m}{x^n}=\frac{a}{b}x^{m-n}\qquad(*)
    \]
    If $m\ge n$, then the resulting expression is a monomial, but when $m<n$, we say that $bx^n$ does not divide $ax^m$. For example, $3x^2$ divides $6x^3$ and $(6x^3)/(3x^2)=2x$, but $3x^4$ does not divides $6x^3$. If $a$ and $b$ in (*) are integers and $b$ does not divide $a$ but $m\ge n$, then we can still divide the monomials, but the coefficient would be a fraction: e.g., $(6x^3)/(4x^2)=(3/2)x$.

    Thus, to find the least common multiple of several monomials, we need to find the maximum degree of $x$ among those monomials. With respect to the coefficient, it is a bit tricky because I don't know the exact definition you were given. The LCM is divisible by every monomial. But in considering (*) above, do we require that $b$ divides $a$ or not? E.g., do we say that the LCM of $6x^3$ and $4x^2$ is $6x^3$ because it is divisible by $4x^2$, even though the resulting coefficient is $6/4=3/2$? Or do we say that the LCM of $6x^3$ and $4x^2$ is $12x^3$ because $(12x^3)/(6x^3)=2$ and $(12x^3)/(4x^2)=3x$, and in both cases the coefficients are integers?

    If we require that coefficients are divided evenly (which is more likely), then the LCM of $35x$, $5x^2$ and $7x^3$ is $35x^3$. Indeed, $(35x^3)/(35x)=x^2$, $(35x^3)/(5x^2)=7x$ and $(35x^3)/(7x^3)=5$. The power of $x$ cannot be less than 3 because the LCM must be divisible by $7x^3$. If we don't require that the coefficients divide evenly, then the LCM is $x^3$ or $cx^3$ for any non-zero real number $c$ because $x^3/(35x)=(1/35)x^2$, $x^3/(5x^2)=(1/5)x$ and $x^3/(7x^3)=1/7$. These are still monomials, though with rational, instead of integer, coefficients.

    You see that it would be more efficient to consult a textbook.

Similar Threads

  1. Commutative ring | Exam question
    By Krizalid in forum Challenge Questions and Puzzles
    Replies: 4
    Last Post: August 21st, 2013, 08:18
  2. practice test for final exam
    By CosmoK123456 in forum Basic Probability and Statistics
    Replies: 1
    Last Post: August 13th, 2013, 21:52
  3. Exam prep part 2
    By Bmanmcfly in forum Calculus
    Replies: 3
    Last Post: May 21st, 2013, 01:52
  4. Exam prep part 1
    By Bmanmcfly in forum Calculus
    Replies: 6
    Last Post: May 17th, 2013, 20:53
  5. Exam Log Question
    By CaptainBlack in forum Pre-Calculus
    Replies: 1
    Last Post: March 24th, 2012, 02:48

Tags for this Thread

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •  
Math Help Boards