laminar flow in a pipe will get its maximum velocity in the very center of the pipe. the profile is a parabola. U function of the radial position U=U(r); Radius = R; U(0)=Umax and U(R)=0
u(r)=Umax*(1-r**2/R**2)
Umoy is indeed equal two the half of Umax.
do you need more info about how to get...
Hello,
I am working toward my new Stirling engine prototype for a particular application. Let me start with a small description of what I am going to try anyways:
I will experiment this with a small electrical heater:
- heat input: 50-100 W (heater thermall insulated on all sides but the...
I have not found anything :D - originally experimenting stirling engines (basically making pressure, temperature measurements from a stirling engine installed on an electrical heater). Not that I have worked on this for a long time but a good way I found to improve efficiency of this stirling...
if you take this backward:
you use a fluid with a higher boiling point in HP#1 than in HP#2.
then you always have T1>T2, so heat can keep moving. so you can connect Condenser#1 to Evaporator#2 and still have the system working.
Yes I understood that but I am basically wondering what would happen if you are cooling the first condenser with the second flask evaporator. then you cool down the second condenser with a heat sink.
the way I understood this paper was that the second heat pipe fluid would boil at a higher...
Hello guys,
Introduction: I would like to get some input about some kind of temperature amplifier.
What I have, is:
- an electrical heater (basically a resistor that is heating a square piece (20x20 mm, 50-100 W) of copper). It's insulated on 5 sides of the copper cube. Only one side is...