Recent content by zm1046838471

I overlooked your reply carelessly. Thank you and I get the point now.

Thanks! I had revised my descriptions.

Thank you! It is helpful.

Thank you! I can get something like Xn+1=[(a×Xn+c)/d] mod m, Xn+1=[(a×Xn+c)] mod m now.

What I get is [X][/n]:cry:

[X][/n]

I revised my descriptions just now.

This is my first question here. I tried my best to work out it by myself but it didn't work. I'm reading Computational Methods in Physics and Engineering by Samuel S M Wong recently. I don't know how to deduce Eq.(7-2) on page 299 of this book. There are some paragraphs on this page as...

Thank you. Nice to meet you!

Hello! My name is Min Zheng. I'm from China. I like physics. I heard about this website just now. I'm sure that I can learn a lot here.