Recent content by WyattKEllis

Thank you! I was definitely on the wrong track. Now I've identified y_h(t)=C*(e^t) as the homogenous solution and y_p(t)=((t^3)-(t^2)+5t-6)*(e^t)+((t^3)-(t^2)+5t-6)*(e^2t) as the particular solution which I believe is appropriate. So this solution family satisfies some first order linear...

I identified the root 1 with multiplicity 1 and the root 2 with multiplicity 1. So The characteristic equation is ((m-1)^2)*(m-2)=0. Simplifying and substituting with y I found: y'''-4y''+5y'-2y=0. So now I've realized that this is actually describing y(t)=(C1)*(e^t)+(C2)*(e^t)+(C3)*(e^2t) and...