I am wondering if I am using the wrong metric to measure the table's stability (vertical load before tipping).
With the diagram adjusted to be a sideways force on the top, what would the equation look like to get the table to start to tip?
Thanks for the help. So, if I understand this correctly. The vertical measurement of the center of gravity has no impact on the amount of force required to start to tip the table, it only has an effect once it begins tipping.
Regardless of a heavy top/light base combination or vice versa, the...
ok, so am I correct in adding the weight for the top and the base together to get W?
Or is W only a percentage of that, since some of the weight of the top is outside of the tipping point and would therefore be contributing to the load L?
Thanks for the quick reply.
I don't think you understood my question entirely. I will try to rephrase and make it clearer.
I understand that the table will tip once L>Wa/x, as you say the tipping torque is greater than the restoring torque of the weight.
I am not concerned about the tipping...
I would like to understand the topic discussed in this thread more. https://www.physicsforums.com/threads/tipping-over-a-table-how-much-overhang.1012197/post-6598527
As I understand it, I can find the load required to tip the table can be calculated by this formula. L<W a/x
This is illustrated...