There's no advantage in using gamma rays to burn things, a 1kW visible/IR laser would be far more effective than a gamma ray laser of the same power for burning things.
The only uses I see are damaging radiation sensitive equipment as stated and giving people radiation induced illness..
I...
I've played around in FL studio. Never studied music or an instrument other than the compulsory classes early on in school, but its a fun way to be creative on a computer.
Here's some simple compositions I came up with http://soundcloud.com/carrotsnack
I like to mix instruments of different genres.
Nearly every online article and video I see talking about EDL have comments from people who are uncertain about the complexity of the landing. You are definitely not alone.
Check out the previous "Six Minutes of Terror" of video
Back then many people were unsure it would work, but it work...
As you move further away from the Earth's surface, the value of g decreases proportional to 1/distance2. Only at sea level is g ~10m/s2. You do have to be very high though until you notice the difference, for the astronauts in the international space station g is still > 9m/s2.
Maybe another way to phrase the question would be that there is a space probe stationary 1 AU from the Sun firing its thrusters towards the Sun to stop it from falling towards it. All of a sudden the Sun disappears from the area (rapidly accelerates elsewhere or an anti-Sun annihilates with it...
Don't let the units confuse you, in place of G just use 6.67*10^-11
Also your value for c^2 is wrong, it should be 300,000,000^2 = (3*10^8)^2 = 9*10^16
If the "-" represents the ground or reference then I believe the "+" can have any potential difference whether positive or negative. In such a case though the "-" terminal will have the higher potential and so conventional current will run from it to the "+" terminal.
The accelerometer will only measure acceleration, it cannot tell the difference between being stationary with respect to the Earth or moving at a constant velocity. You can integrate the acceleration data to obtain velocity information, but it will likely become inaccurate over time.
Thanks for going to effort of running a simulation, it seems my prediction was true despite my limited knowledge of magnetism. Also a 25% increase will actually make the thinner magnets slightly more effective than the thicker ones for my use, so given imperfections it should be about equivalent...
I'm not entirely sure how the sheet will affect the field but I expected something like this:
http://img805.imageshack.us/img805/3425/magneticfield.jpg
Is this what will happen? To simplify things, will this increase the field density in the small volume above the magnet like in the...
I'm currently playing with diamagnetic pyrolytic graphite and I have created a small portion of a track similar to this video
I want to create a circular track for it travel on, but as rare Earth magnets are getting expensive I'm going to use thinner magnets that consequently have a weaker...
You're right, it is the speed of light, although it is yet to be experimentally measured. You're also right that the planets will lose their orbit in order of distance from the Sun.
Skip to 7:20 in this video for a visual explanation
Hopefully someone else will give more information.