Recent content by Vivek98phyboy

  1. Vivek98phyboy

    Reflection of inverted waves to form a standing wave

    Standing waves in a string fixed at one end is formed by incoming and reflected waves. If reflected waves are 180° out of phase with incoming wave, how could they combine to give an oscillating wave? Shouldn't it be completely destructive interference all the time across the whole length of string?
  2. Vivek98phyboy

    Contradiction in Phase of reflected sound

    While studying the fundamentals of sound waves in organ pipe, I noted that the fact about phase of reflected waves is contradicting while referring multiple sources This book of mine describes the reflection from a rigid surface/closed end to be in phase Whereas this one describes the...
  3. Vivek98phyboy

    What are the other forces acting on ##dm## in addition to gravity?

    After solving using energy conservation, I found the angular velocity at 37° to be omega=2.97/(L)^½ Tension and the weight (dm)g are the two forces acting on the tip dm To find the resultant force, I resolved the centripetal force and tangential force to find the centripetal force as F=...
  4. Vivek98phyboy

    What am I Missing? Solving Conservation of Energy

    I didn't notice this. Thank you for pointing out this fact
  5. Vivek98phyboy

    What am I Missing? Solving Conservation of Energy

    You are right. When I took friction into account, I got it right. Thank you
  6. Vivek98phyboy

    What am I Missing? Solving Conservation of Energy

    By solving conservation of energy, I was able to find the linear velocity which is [10g(H-R-Rsin(theta))/7]^½ and by differentiating this with respect to "t", I arrived at the tangential acceleration value of -(5gcos(theta))/7 and found it to be in agreement with the solution provided in the...
  7. Vivek98phyboy

    Force due to Surface tension here

    So the surface molecules often swapping their positions with the one moving to the surface experiencing stress due to attraction along the surface would be the right way to think?
  8. Vivek98phyboy

    Force due to Surface tension here

    I also thought of it in this this way. If the surface is under tension then there could be a situation in which the molecules are unable to move down individually as the whole surface is being pulled down like a ball bouncing from a floor packed with balls. Is that a right analogy?
  9. Vivek98phyboy

    Force due to Surface tension here

    I just checked across few websites and it said that the downward force may sometimes pull the molecules into the bulk liquid but as soon as it goes in, another molecule from the inside rushes to fill the gap. If is it so, then from where does the molecule get energy to move upwards?
  10. Vivek98phyboy

    Force due to Surface tension here

    So, do you mean that the net force is different when look at it as a whole surface from looking at it as a molecule?
  11. Vivek98phyboy

    Force due to Surface tension here

    Why does the force due to surface tension act parallel to the surface here? I know that surface tension is a result of absence of cohesive force above the surface and thus the water molecules below pulls the surface down and keeps it like a stretched membrane. If the surface is pressed as...
  12. Vivek98phyboy

    Reason for Calculating Surface tension

    They directly stated that pressure on the patch= surface tension along perimeter But I am expecting an explanation for not considering the surface tension in curved part
  13. Vivek98phyboy

    Reason for Calculating Surface tension

    I haven't got any good response till now. Can someone help me understand this
  14. Vivek98phyboy

    Reason for Calculating Surface tension

    If i were to integrate it across the curved surface then i would get T×2πr² but it won't give you the answer
  15. Vivek98phyboy

    Reason for Calculating Surface tension

    But as far as I've checked all the books and internet, there is no such example of using integral over the hemispherical surface. All they did was calculating T×2πr by only considering forces due to the other hemispherical part along the periphery.
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