Beautiful - love how Feynman derived the J0 series using the exact same arguments I put forth. So it is indeed an infinite process - where a change in E is always accompanied by a change in B and vice versa. Let's just hope there's always a J0-like series we could use to get a resultant E(x,t)...
So if I'm looking at this correctly - the changing magnetic field is accompanied by an electric field such that Faraday's law is satisfied (ie. curl E = -dB/dt). The induced electric field isn't caused by the changing magnetic field, rather, the induced electric field is a consequence of the...
So changing magnetic fields induce electric fields (Faraday's law when the magnetic field is changed by either moving the source or by changing the current in the source that's causing the magnetic field, ie. we're not moving the conductor where an emf is induced so there's no f=qvXB).
Also...
Hello everyone,
This is in reference to fig 5.19 (screen shot attached - please read the paragraph which says "Figure 5.19 shows the...").
I don't get why the field outside of the sphere of radius ct acts as though the particle would have continued its motion. Author's words : "The field...
I think it'd be better to genuinely understand the chapter in a few readings and realize what message its trying to convey-then go through the problems to try and get a mental revision of what you just learned and see if they could be applied there-directly or indirectly.And if you feel you can...
Hello guys,great to hang around in these forums:smile:
I've been really wondering about the content of my statement of purpose/statement essay.I'll be applying to grad schools soon either for nuclear or some specialization areas in mechanical.Although I'm from a Civil engineering background,I...
shotgun effect??Please explain?:confused:
And damn,you must have really good acads and other stuffs if you're applying to those sort of universities.
Also,any idea as to how many students apply in NE masters programs across USA?(In terms of percentage of students applying for a more famous-lets...
So the gradient in polar should ACTUALLY look like this?
∇U(r,α,β)=rδU/δr+αδU/(rδα)+βδU/(rsinαδβ)
But the custom is the take r and rsinα outside the brackets because they have constant magnitude in the differential lengths-rδα and rsinαδβ-in the direction of α and β respectively?
Ok,I think I got it.So its like the gradient components for the angular directions are the rates of changes of the potential U "in the direction of" theta with the arc length being rd(theta) and phi with the arc length bring rsin(theta)d(phi)-hence bringing in the denominator r and rsin(theta)...
I'm sorry but I'm not able to visualize what you are saying.
I thought that the components of the gradient are concerned with the rate of change of the potential in each direction?
Let's say we have a scalar function U in terms of r,theta and phi.
why cannot this be the gradient at any point P(r,theta,phi)-
partial of U wrt. r in the direction of r+partial of U wrt. theta in direction of (theta)+partial of U wrt. phi in the direction of (phi)?