The formula that you provided for the orbital velocity above is indeed the right interpretation of the question. I perhaps either copied it wrong or didn't use the right formula. I'll try to solve this question using your formula. Thanks =)
I was told that the distance is equal to the radius which is equal to 2.00 x 10^8 and that the velocity is 7000 m/s for the faraway planet.
Once I plug these values into the formula it looks like
(6.67 x 10^-11)(Mass of planet)= (7000)^2 x (2.00 x 10^8) / a
However what do i do with the...
Homework Statement
So my professor gave me this formula GMplanet = (v^2 x d)/a to solve for the question and told me that m/v = density. I was told then to multiply the end result of m by 1000 and v by 1,000,000 to get the answer. I am given all the knowns except the acceleration. How do i...
Oh ok. The only knowledge i have of angular velocity is it determines how fast something is turning. So wouldn't the angular velocity be proportional to the velocity and since the satellite is going to a higher orbital, the speed would thus decrease and so if angular velocity is decreasing...
Homework Statement
Question is in attachment
Can someone explain to me what the infinity sign is I'm new to this topic.
All I know is that as a satellite goes to a higher orbit that the velocity decreases.
Oh I made a careless computation error I input all the values at once in my calculator and got 181.75 ≈181.8.
(27^2)(4.10x10^6)^3/ (1.15 x 10^6)^3 = 33035.85699
radical of 33035.85699 = 181.75 = 181.8 Cheers! =)
Consider a moon that is 1.15 x 10^6 km from the planet it is orbiting...
Homework Statement
Consider a moon that is 1.15 x 10^6 km from the planet it is orbiting. This moon makes one complete orbit every 27 days. What is the orbital period of a satellite orbiting the planet at a distance of...
The only formula I derived from was the F= Gm1m2/r^2 formula which I then got to be g=m^2/r^2 and eventually V= √Gxm^2/r. However I can't seem to find a simplified version of just speed and radius to prove my point. =/
Good point! Perhaps since it is going in a circular orbit (I'm assuming a tangential direction around the circle) , the speed increases as the radius decreases and vice-versa. I don't think mass would influence an object's speed when going around in a circular orbit. Please correct me if I'm...
I think the answer is based on the formula V= √g x m^2/r hence v is inversely proportional to r not m. Hence the greater the velocity the lesser the mass. So velocity is dependent on radius not mass.
Homework Statement
You can determine the velocity of a satellite in uniform circular orbit by applying Newton's second law, Newton's law of gravity, and the centripetal acceleration due to gravity. Which of the following is not correct?
a) The orbital radius r and the speed v cannot be...
A moon is orbiting around the planet with a constant distance of 4.0 x 10^8 with...
Homework Statement
Question/w formulas are in attachment.
I know I've been given two masses, 5.5 and 7.35 x 10^ 22 kg, and a distance of 4.0 x 10^8. But what I don't understand is the speed of 950 m/s and...