Hmm... It makes sense now. I mean, if x = 0 (equilibrium position) in a SHM the acceleration should be zero (there's no force acting). And in extremes it gets the highest amount of acceleration.
I understand it now! :partytime: Thanks, really! thank you!
##a=-\omega^2x##...
I know the main concepts (e.g. how to calculate the velocity of a particle in a certain point, how to find the position of a particle in a SHM, I understand those equations x = A cos ( ωt) v = - Aω sin ( ωt)) but I don't understand that accelaration part!
For example, I saw this explanation...
Hello Kuroman! Thank you! :smile:
When I think in SHM I instantly remember a pendulum or a a block connect in a spring. I imagine SHM a classification of this kind of moviment that "always come back and repeats." Oh, and I also remember about trigonometric functions and some sin or cos...
Hello guys!
Today I was studying SHM and I can't understand how to proof that a = -ω2Acos(ωt+φ) gives me accelaration of particle executing simple harmonic motion!
If someone "build" this equation step-by-step I would be really thankfull!
:)