Sorry when I said solve I meant evaluate.
Could I switch the order of integration so when I evaluate after integrating a second time I lose x and y from the equation?
Well I started by integrating with respect to y and got ye^(-x^2)dx,I then solved for the values y=x and y=0 leaving xe^(-x^2)dx and unsure of if my first steps are correct and how to continue.
My idea for a next step would be integration by substitution u=-x^2 but unsure as to whether that...
Homework Statement
Please help I need to find the area of e^(-x^2) with the domain 0 is less than or equal to y which is less than or equal to 1 and y is less than or equal to x which is less than or equal to one
Homework Equations
The Attempt at a Solution
I set up the...
Homework Statement
Find an equation of the line passing through the point (1, 4) such that the area of the triangle formed by this line and the positive coordinate axes is as small as possible.
Homework Equations
The Attempt at a Solution
No idea where to start this one please...
Homework Statement
A 1.00 mol sample of an ideal monatomic gas is taken through the cycle shown in the figure. The process A B is a reversible isothermal expansion where PA = 5.0 atm, PB = 3.0 atm, VA = 30.0 L, and VB = 50.0 L.
(a) Calculate the net work done by the gas.
(b)...
Homework Statement
Find the point(s) on the graph of the function at which the tangent line has the indicated slope. (If an answer does not exist, enter DNE.)
g(x) = (1/3)x^3 - (1/2)x^2 - 4x +8
mtan=-4
Homework Equations
[b]3. The Attempt at a Solution
firstly i derived...
ahh i give up for one night :) 3 hours on one question is longer than i spent completing all the previous 6 questions on the assignment.
will look over it again at some point during the weekend. Dont make plans to keep busy :)
thanks once again
part a) f=mg-mkv^2 = ma =(this is where i may go wrong) m(dv/dx)(dx/dt) =m(dv/dx)v
limited knowledge of differential equations but here goes
x = -∫(v/(kv² + g))dv = -(1/(2k))ln(kv² + g) + C.
final velocity = initial velocity (v=u) when x = 0, C = (1/(2k))ln(ku² + g).
Therefore -2kx =...
no integration needed is the best news i have heard for a while :)
i have looked at terminal velocity and think i am getting somewhere with that
terminal velocity is reached when force due to gravity = air resistance
mg=kv^2
air resistance can be written as 1/2 (drag coefficient x density x...