Recent content by User1265

  1. U

    A transverse wave traveling through a medium versus a particle of the medium

    I imagine a particle traveling across 1 wave cycle. The total vertical distance traveled across the wave cycle is 4 x the amplitude of the wave. The total vertical distance traveled in 1 minute: 5 cycles in 1 second, thus 5x60 cycles in a minute then 4 x amplitudes effectively traveled per...
  2. U

    Multiple choice Q: Mangetic fields and Spring Constant

    My attempt at a solution: Is my logic accurate/correct, and is my answer correct? I consider the forces acting to be: Restoring forces in springs parallel, and Force of the current-carrying conductor in the Magnetic field. I imagine a vertical displacement of y upwards ( direction determined...
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    Question on a textbook statment on Rutherford Scattering

    The experimental observation of finding very few alpha particles scattered through large angles (>90) - I thought this would have inferred that the positive charge of the core of the atom (which we now come to know as the nuclei) must have been great in order greatly deflect alpha particles...
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    Understanding the Minimum Speed to Keep Carriage on Tracks in a Loop

    Thanks for the reply. I just don't understand how that means a carriage in contact with the tract will be instanteously in free fall, as surely if it is in physically in contact with the tract, there must be a force exerted by the tract, as the normal force is a contact force, so the net...
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    Understanding the Minimum Speed to Keep Carriage on Tracks in a Loop

    I recognise that the normal force must alwayss act towards the centre of the circle loop, as the rail always has to be exertign a pushing force on the car/carriage in order for it to follow the trajectoryof the loop. However , I cannot understand why, the reaction force has to be greater than...
  6. U

    Solving a Spring-Mass-Box System:Energy Conservation

    Upon reading, realized that equations of consevation of energy would be of use for this question. I considered the energy of the system - the spring mass and box - taking into account that there will be Elastic potential energy of the spring, and we can arbitrarily set the intial positon(A) of...
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    Derivation of the oscillation period for a vertical mass-spring system

    Why change in tension and not tension is proportional to displacement at an instant in the elastic cord as the cord is originally displaced from its natural length?
  8. U

    Derivation of the oscillation period for a vertical mass-spring system

    Thank you, and the restoring force proportional to -ve displacement?
  9. U

    Derivation of the oscillation period for a vertical mass-spring system

    But doesn't the elastic force in the cord acts towards equilibrium too ?
  10. U

    Derivation of the oscillation period for a vertical mass-spring system

    So what would be considered the restoring force? Is it just the tension or the resultant force which would be acting towards the equilbrium?
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    Derivation of the oscillation period for a vertical mass-spring system

    I understand the derivation of T= 2π√m/k is a= -kx/m, in a mass spring system horizonatally on a smooth plane, as this equated to the general equation of acceleration of simple harmonic motion , a= - 4π^2 (1/T^2) x but surely when in a vertical system , taking downwards as -ve, ma = kx - mg...
  12. U

    Energy Conservation as an explanation for v=0 for spring mass system

    My Solution: For the displacement graph, the gradient is crucial to predict the behaviour of the displacement of the block through time. At 1: System is released - velocity is zero, considering forces acting on block, kx < mg, as block is observed to move downwards, and object is...
  13. U

    Catapult spring, Kinetic and Potential energy

    X is the total length of the spring after compression. L is the natural length. With regards to the latter question, is my reasoning correct for the point of maxium velocity: when ball loses contact with the spring, it's velocity is a maxium for the reason, when the spring is extended down by...
  14. U

    Catapult spring, Kinetic and Potential energy

    At the point the ball leaves the spring I believe the upwards speed would be reducing due to the force of gravity on the ball. But what I don't understand is why h=x-l , why is the gravitational potential energy mg(x-l) when ball leaves the spring?
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