Stiil pretty much stuck with this one? Using Housner paper the max shear force that can be produced by the half filled tank is; T = 2*π√m/k ∴ T = 2*π√500/1000 = 4.443 seconds. This is the period of oscillation therefore shear force F = (2*π/T)/m = 500/(√500/1000) = 707.1 N. The answer given in...
Yes you're correct, T (period of oscillation) = 2*π√m/k. Therefore F (max force produced) = (2π/T)*m. I'll have to σo through the paper properly & post once I have a more thorough understanding. Thanks for your input, back asap...
It's not 100% clear to me either, but if you look at page two of the attached .pdf below. It seems that what I've been given is a simplified model where the mass of the water (m) is 500 kg & the equivalent stiffness of the building is (k) 1000 N/m. It then asks me to find the shear force?
pdf...
Homework Statement
A half-full water tank mounted on the top of a building is modeled as shown below. Find the shear force it can produce?
m = 500 kg
k = 1000 N/m
model: https://app.box.com/s/qke2kbwag2mp9a23kkqq
Homework Equations
Transfer Matrix Method:
Point & Field Matrices...
No my post was in response to your post (post # 87).
My solution regarding my system i.e. K1 = K2 was to find the open-loop tf. The equation I used to do this was: https://app.box.com/s/arwnrxwopi6y2cjls42q
Did I enter an incorrect tf in order to plot 'root locus' of system when K1 = K2 ?
Is...
In response to 'milesyoung' post #87;
Closed Loop Tf: https://app.box.com/s/twk1h23blxebgawzaw7d
Characteristic Equation for post #87: https://app.box.com/s/qivkcx0b0csz6xx8oe8e
Miles I have submitted my report. I must thank you for all your help & suggestions. Now that the project is...
G(s): https://app.box.com/s/s7szsp7rztjndh58oolc
H(s): https://app.box.com/s/8hn2fryguhnis8mr0469
F(s) open loop tf when K1=K2: https://app.box.com/s/arwnrxwopi6y2cjls42q
Root Locus of F(s): https://app.box.com/s/wzaupxumo3j96lvjwobo
2nd Order Approx K1=K2...
-K1*H(s)*(G(s)/1-H(s)*G(s)*K2s ?
H(s) = 2/(s+2)
G(s) = -0.125(s+0.452)/(s+1.25)(s^2+0.234s+0.0163)
Therefore as I originally said , find closed loop of H(s), G(s) & -k2s
the open loop is then: the closed loop above * -k1
Root Locus Plot:
Open Loop Bode Plot...
But that's exactly where I'm stuck, I've done everything but I'm not sure how to get the 'open loop' with velocity feedback i.e. K1=K2. For the 1st system you just multiply :
-1*2/(s+2)*G(s)
But how do you work out the open loop tf with velocity feedback? Not sure how to deal with the closed...
One last thing I was going to ask, as I've asked you countless questions so far. Is for Q6,7 I've got to repeat the earlier Q's i.e plot root locus & do the 2nd order approx. This time I include (-K2s). I've been trying to resolve the TF I should use. Till now it's been 'open-loop',
Would I...
No. Are these markers of the gain (K)? I've tried to move them in order to adjust the reponse but it just becomes totally unstable?
Edit: moving the 'pink dot' to -1+/- 2j I've reduced the Ts to under 4 secs but the PO is 22.6%. Does this mean I would have to use the same process again to get...
When I produce the 'step' response, the overshoot is gone but it still has a settling time of 36 secs. How would I go about reducing it to the design specs?
I get the exact same plot as I did before, with no intesection at s = -1 =/- 2j ? In the example above for C, it shows the zero as s = -1 ? Is this the value I should be using, as I've been using s = 1.58 ?
If I use the s=-1, then I get a plot that quite similar but with the intersection at s=...