I'm not sure exactly where you are getting at - Wouldn't adding the resistors at "equivalent locations" be on the same component, so e.g. we put the resistors on both capacitors not a capacitor and an inductor?
However, your comments made me realize the solution:
If I can make ##Z_L = Z_C##...
If we ignore the resistors, we will see that for the two paths:
$$ V = I_1 (Z_1+Z_2) = I_2 (Z_2 +Z_1) $$
$$ I_1 =I_2 $$
So the current that runs through the pair is equal to each other.
However, I cannot see how we can just ignore the resistors? I get that we can conclude that their reactans is...
(This is my first time posting here, sorry in advance for any difficulties. )
All componenets of same type has same magnitude, so e.g. the two resistors both have $R$ resistance.
Given the difficulty of the previous exercises, I believe I'm over complicating the problem. However, here is what...