Recent content by tmle04

i don't get it..so the angular speed of the rotating hoop w = ? and the angular speed of the speed of its center v = Square_Root_Of_((4/3)gh) ... ??

ur equation is correct... i don't kno why 4pi = 1/2*a*(0.480)^2 mastering physics accepteed his answer but mine...

my roomate is helping me right now...he did dis already...ill let u kno when i figure it out...

i don't kno I am confuse...anyway i kno omega2 = (2/0.480)*2pi

iam using ur equation...it should be 2 rev per .480 second...then u time 2 pi...do u go to asu?

ignore da above comment...it should be... -(2/.480)2pi*t = 1/2*a*(0.480)^2... now tell me wats ur time after one revolution?and how did u get it?

it should be... -4pi*t = 1/2*a*(0.480)^2... now tell me wats ur time after one revolution?and how did u get it?

whered da 4pi come from?

what is t in that equation? time after 2nd revolution or 1st revolution. also how can i solve it when it did not give the angular acceleration?

17m is not the right answer...

i don't kno if the rocket has zero velocity at maximum height...it didnt say in da problem...

so the 910 J is the KE and if so...KE = (0.5*1.25*(v1^2)) + (0.5*.240*(v2^2)) ?

i have no clue...omg...my head hurts trying to understand this problem..ahhaahah

i meant 2.70*10^7

A fireworks rocket is fired vertically upward. At its maximum height of 75.0m , it explodes and breaks into two pieces, one with mass = 1.25kg and the other with mass = 0.240kg . In the explosion, 910 J of chemical energy is converted to kinetic energy of the two fragments. a) What is the...