So let me ask this... You have 2 space probes just sitting in space. One has a mass of 100. The other has a mass of 30. You want to accelerate both to a velocity of 50. Would they both require the same amount of rocket force? Or would the larger one require more?
Mars gravity is 1/3 the Earth's. Moons gravity is I believe about 1/7 the earth. Mars is radius is 2,106 miles. Moons radius is 1,079 miles. So quite a difference.
I'm curious of what the weight of fuel would be to land and take off from Mars would be? I know it all depends on payload, but would it even be possible to blast a rocket from earth, with enough fuel to get to Mars, land on Mars, blast off from Mars, and then return to earth? My guess is that...
Found this interesting interactive experiment.
http://hubblesite.org/explore_astronomy/black_holes/encyc_mod3_q14.html
In the interactive, it looks like the black hole is orbiting around something. What would it orbit around? Or am I looking at it wrong?
I remember reading about how a city could be seen across a sea at certain times. But normally would not be seen because of Earth's curvature. At certain times however, it could be seen because of light bending. I can't remember what the cause was though.
Anyone know about this and what caused it?
Just to avoid confusion, we're looking for gravity of each individual object, not the attraction between them.
I was actually thinking of a formula that included the radius of the hollow section (r) and total radius (R).
g = Gm/(R+r)(R-r)
Not so sure tho... Its probably just the normal...
Consider the 2 objects in the pic. They both have the same mass of 200 kg. They both have a radius of 4 meters. However, the object on the right is hollow, with the walls being 2 meters thick. For the gravity equation, and the object on the right, does one use a radius of 4 squared, or the wall...
After an electron absorbs a photon, it will move to a higher energy state. It then releases a photon and returns to its ground state. But why does the electron release the photon? Why does it not remain in that energy state? What forces it to return to ground state?
ya. N/kg doesn't sound right. Its for finding the gravity on planet X. If the object has 1 J/kg of gravitational potential at .5 meters from the surface, what is the gravity on that planet?
So Vg = gy so g = V/y. So, 1/.5 = 2
The gravity on that planet is 2 m/s? But they want the answer...
apparently, the correct answer is the amount of energy added, or 1200J. This is an isobaric situation so I guess W=PV doesn't work?
All my research on the 'net points to W=PV though...
<Moderator's note: Moved from a technical forum and thus no template used.>
Consider a gas in a closed container with a piston allowed to move. Let's start with a volume of 15 and pressure of 1.5. We add heat to the system, let's say 1200 J. This forces the piston to move increasing the volume...
A question on a test that i got wrong.
If you exert a force of 25 on a plunger of a cylinder containing air with an initial volume of 7, then exert the same force on the plunger of a smaller diameter cylinder, but with same volume of air, the cylinder with the larger diameter will compress...