Recent content by TimNJ

That makes a lot of sense. Thanks. I guess I still have some confusion with respect to the different electric fields, specifically how they change with time, and how that relates to the charging behavior of capacitor. I've ordered an old edition of a book "Matter & Interactions" by Sherwood...

Yes! From a circuit analysis perspective that certainly checks out! Thank you for that.

Thanks. I like thinking of it that way, I think. Here's what I take from that: If the source voltage is changed, then there will be a transient state, during which charge redistributes and voltages reach equilibrium. Even if there are just two unconnected wires hanging off a step-voltage...

Thanks RPinPA. I guess that's why the peak current is simply V/R? So with normal conductors, there is a high initial current, but it is so brief that we don't even worry about it in most analysis? In a capacitor, charge continues to flow until the voltage reaches equilibrium?

Hi all, I'm trying to wrap my head around the physics behind the current that initial flows when a voltage step is applied across a capacitor. Namely, why does a large current initially flow into a parallel plate capacitor, but a large initial current does not flow if the capacitor is replaced...

Okay, sorry I was really under the impression that there was still quite a bit of design work being done in the US. Maybe it's not solely in the US as it was a couple of decades ago but still jobs to be had. And actually AD and LT were exactly the companies that came to mind when I was writing...

I literally just searched "semiconductor jobs ohio". It's really not worth it to outsource that kind of work. A "fabless" company (meaning they don't have the equipment/factory to manufacture a chip) might collaborate with an overseas manufacturer to get their design made but most of the design...

I'm a senior electrical engineering student from New Jersey. Good choice, I've really enjoyed what I've learned so far. The job opportunities for both EE and CE are vast. While you are correct that a lot of the semiconductor research/manufacturing is done in California, there are definitely...

Thank you Simon, So if drag is dependent on the velocity squared, but I don't know what my velocity will be vs time and at different altitudes, how can I compute this? That is, how can I figure out what my ΔV(drag) is when drag itself is a function of velocity? Am I missing something in the...

Thanks, So I have KE = PE(gravity) + W(drag). That is, 1/2mV2 = GMm/r + W(drag). Now W(drag) is the integral of F(drag), which should equal F(drag) * distance, which is 0.276v2, in my case. I got that by multiplying Δx, (100km-35km=65km), by the drag coefficient I calculated at 35km, 4.257 x...

Hi everyone, I'm working on a project for my electromagnetics class which asks us to design an electrostatic launch system that can propel an object into space. Though the bulk of the project is supposed to be about designing the accelerator plate array, I got really interested in the whole...

Yes! I am still here! I am so grateful for the insightful discussion this has brought about. I was actually studying for an engineering exam and just couldn't get around to logging on to PF. Just to clear a few things up, I understand the ideal model very well, and for the most part I...

Thank you everyone for your replies. I've been scouring the internet from allboutcircuits, to stackexchange, to edaboard, to eevblog, and so forth...and I basically keep coming up with the same "answer" to my question. I think the real answer must be more complex than I thought. LvW, I guess...

Hi everyone, I've been seeking the answer to this question for a long time. I've looked at posts like... https://www.physicsforums.com/threads/op-amp-transient-state.855512/ and https://www.physicsforums.com/threads/how-does-negative-feedback-in-an-op-amp-work-conceptually.584881/ ...but I...

Absolutely wonderful response. Thank you so much. I understand that power is a product of two quantities. I'm assuming that the magical power regulator box has a method of varying power. In simplest terms, I take it that pressure is determined by the system the pump is attached to (valves, heat...