Ok, so I found the average acceleration to be 7.3 x 10^3 however, the direction I got was 75degrees N of W. Here's what I did:
|Vx| = 21 m/s(cos22) - 26 m/s(cos22)
= -4.64 m/s
|Vy| = 21 m/s(sin22) + 26 m/s(sin22)
= 17.6 m/s
aav,x = -4.64/0.0025 = -1856 m/s^2
aav,y =...
These were my calculations:
|Vx| = |Vfx| + (-|Vix|)
= 21 m/s(sin68) - 26 m/s(cos22)
= -4.6 m/2 oops, i got -4.6 but on the next page i left out the negative, not sure if that is the real problem though
|Vy| = |Vfy| + (-|Viy|)
= 21 m/s(cos68) - 26 m/s(sin22)
= -1.9...
Problem: A hockey puck rebounds from a board as shown in figure 16. The puck is in contact with the board for 2.5 ms. Determine the average acceleration of the puck over the interval.
t = 0.0025 s |vi|= 26 m/s |vf| = 21 m/s aav = ? *v and a are vectors*
I have made several attempts to...